I am about to calculate the duty cycle of the injectors using VAG-COM log (002). I've already checked Glenn's "study" regarding to this topic. He got bigger values than 100% which was strange for me. How could an injector be kept opened longer than 100% (all the time)?
My theory is the following:
I've calculated the duration of a full revolution. Lets say at 6000 RPM, it is 10ms. (1sec/(6000RPM/60)=0.01s=10ms).
I've taken the Inj. On Time (from the VAG-COM log 002) and divided this value with the duration of four full revolutions (4*10ms). Why four? Because our engines are four strokers and a single cylinder will fire in every fourth rev.
According to this, if the Inj On Time was 25ms, the duty cycle got 25/40 * 100 = 62.5%.
Am i correct?
My theory is the following:
I've calculated the duration of a full revolution. Lets say at 6000 RPM, it is 10ms. (1sec/(6000RPM/60)=0.01s=10ms).
I've taken the Inj. On Time (from the VAG-COM log 002) and divided this value with the duration of four full revolutions (4*10ms). Why four? Because our engines are four strokers and a single cylinder will fire in every fourth rev.
According to this, if the Inj On Time was 25ms, the duty cycle got 25/40 * 100 = 62.5%.
Am i correct?
Last edited: